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Found in: Page 777

### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

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# A certain ammeter has a resistance of $$5.00 \times {10^{ - 5}}{\rm{ }}\Omega$$ on its $$3.00 - A$$ scale and contains a $$10.0 - \Omega$$ galvanometer. What is the sensitivity of the galvanometer?

The galvanometer inside an ammeter with internal resistance $$r = 10{\rm{ }}\Omega$$ has a sensitivity value of $${I_g} = 15{\rm{ }}\mu A$$.

See the step by step solution

## Step 1: Concept Introduction

A galvanometer is an electromechanical device used to detect electric current. A galvanometer deflects a pointer in response to an electric current flowing through a coil in a constant magnetic field. An example of an actuator is a galvanometer.

The total flow of electrons via a wire can be used to describe the rate of electron flow. Anything that prevents current flow is referred to as "resistance." An electrical circuit needs resistance in order to transform electrical energy into light, heat, or movement.

## Step 2: Information Provided

• An ammeter with resistance: $$R = 5 \cdot {10^{ - 5}}{\rm{ }}\Omega$$
• An ammeter with a scale: $${I_{tot}} = 3{\rm{ }}A$$
• A galvanometer with internal resistance: $$r = 10{\rm{ }}\Omega$$

## Step 3: Calculation for the sensitivity of galvanometer

The sensitivity of the galvanometer is the current that goes through the galvanometer$${I_g}$$. Obtain the sensitivity by noting that $$R$$ and $$r$$ are at same potentials, which gives –

\begin{align}{c}{I_g}r & = {I_R}R\\{I_g}r & = \left( {{I_{tot}} - {I_g}} \right)R\\{I_g}(r + R) & = {I_{tot}}R\\{I_g} & = \frac{R}{{r + R}}{I_{tot}}\end{align}

\begin{align}{} & = \frac{{5\cot {{10}^{ - 5}}{\rm{ }}\Omega }}{{\left( {10 + 5 \cdot {{10}^{ - 5}}} \right)\Omega }}(3\;A)\\ & = 1.5 \cdot {10^{ - 5}}\;A\\ &= 15{\rm{ }}\mu A\end{align}

Therefore, the value of the current is obtained as $${I_g} = 15{\rm{ }}\mu A$$.

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