Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

Answers without the blur.

Just sign up for free and you're in.

Short Answer

A $0.0200 Ω$ ammeter is placed in series with a $10.00 ‐ Ω$ resistor in a circuit. (a) Draw a circuit diagram of the connection. (b) Calculate the resistance of the combination. (c) If the voltage is kept the same across the combination as it was through the $10.00 ‐ Ω$ resistor alone, what is the percent decrease in current? (d) If the current is kept the same through the combination as it was through the $10.00 ‐ Ω$ resistor alone, what is the percent increase in voltage? (e) Are the changes found in parts (c) and (d) significant? Discuss.

(a) The circuit diagram for the series connection of the ammeter in a resistor circuit is,

(b) The total resistance of the combination is $R_{tot} = 10.02 Ω$ .

(d) If the current of the combinate is the same the increase in the voltage is $0.2 %$

(e) Since the results of current and voltage are very small, they are insignificant.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Concept Introduction

The rate of electron flow can be described as the aggregate flow of electrons via a wire. The term "resistance" refers to anything that stands in the way of current flow. To convert electrical energy to light, heat, or movement, an electrical circuit must have resistance.

Step 2: Circuit Diagram

(a)

The circuit diagram of the connection of an ammeter when a $0.02 Ω$ ammeter is placed in series with a $10 Ω$ resistor in a circuit is given below,

Therefore, the circuit diagram is obtained.

Step 3: Resistance of the combination

(b)

A $0.02 Ω$ ammeter is placed in series with a $10 Ω$ resistor in a circuit.

The formula for total resistance is,

$R_{combination} = R + r = 10 Ω + 0.02 Ω = 10.02 Ω$

Therefore, the value for total resistance is $R_{combination} = 10.02 Ω$ .

Step 4: Decrease in the current

(c)

Current through the only resistor is,

$I = \frac{V}{R} = \frac{V}{10 Ω}$

And current through combination is,

$I_{combination} = \frac{V}{R_{combination}} = \frac{V}{10.02 Ω}$

The decrease in current is,

$P_{d} = (\frac{I_{combination} - I}{I}) \times 100 % = (\frac{(\frac{V}{10.02 Ω}) - (\frac{V}{10 Ω})}{(\frac{V}{10 Ω})}) \times 100 % = - 0.1996 %$

Therefore, the decrease in current is $0.1996 %$ .

Step 5: Increase in voltage

(d)

Voltage through the only resistor is,

$V = IR = I \times 10 Ω$

And voltage through combination is,

$V_{Combination} = {IR}_{Combination} = I \times 10.02 Ω$

The increase in voltage is,

$P_{I} = (\frac{V_{Combination} - V}{V}) \times 100 % = (\frac{(I \times 10.02 Ω) - (I \times 10 Ω)}{(I \times 10 Ω)}) \times 100 % = 0.2 %$

Therefore, the increase in voltage is $0.2 %$ .

Step 6: Are the changes significant

(e)

The result for the decrease in current is $0.1996 %$ .

The result ofthe increase in voltage is $0.2 %$ .

These are very small amounts, so they do not affect the circuit in anyway.

Therefore, the results are not significant.

Find Study Materials for

Create Study Materials

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

Step by Step Solution

Step 1: Concept Introduction

Step 2: Circuit Diagram

Step 3: Resistance of the combination

Step 4: Decrease in the current

Step 5: Increase in voltage

Step 6: Are the changes significant

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

Step by Step Solution

Step 1: Concept Introduction

Step 2: Circuit Diagram

Step 3: Resistance of the combination

Step 4: Decrease in the current

Step 5: Increase in voltage

Step 6: Are the changes significant

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Work Energy and Power

Radiation

Astrophysics

Physics of Motion

Scientific Method Physics

Fluids

Torque and Rotational Motion

Nuclear Physics

Fields in Physics

Measurements

Space Physics

Electricity

Physical Quantities and Units

Medical Physics

Electrostatics

Further Mechanics and Thermal Physics

Mechanics and Materials

Engineering Physics

Energy Physics

Force

Particle Model of Matter

Waves Physics

Magnetism

Modern Physics

Atoms and Radioactivity

Dynamics

Electricity and Magnetism

Conservation of Energy and Momentum

Fundamentals of Physics

Kinematics Physics

Circular Motion and Gravitation

Linear Momentum

Rotational Dynamics

Oscillations

Translational Dynamics

Geometrical and Physical Optics

Thermodynamics

Magnetism and Electromagnetic Induction

Electromagnetism

Electric Charge Field and Potential

Turning Points in Physics