Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q9PE

Expert-verified
College Physics (Urone)
Found in: Page 775

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Refer to Figure 21.7 and the discussion of lights dimming when a heavy

appliance comes on. (a) Given the voltage source is 120 V , the wire resistance is0.400Ω, and the bulb is nominally 75.0W , what power will the bulb dissipate if a total of 15.0 A passes through the wires when the motor comes on? Assume negligible change in bulb resistance. (b) What power is consumed by the motor?

(a)The power will the bulb dissipate if a total of 15.0 A passes through the wires when the motor comes on is 66.8W.

(b) The power consumed by motor is 1644 W.

See the step by step solution

Step by Step Solution

Step 1: Definition of Power

Electric power is the percentage of time it takes to work or generate energy and is expressed as the work W or the transmitted energy divided by the time interval t.

Step 2: Calculating P2

(a)

Calculating resistance in the bulb,

RBulb=E2P1 =120V275W =192 Ω

Next step is calculating current flowing through bulb when motor comes on:

I2=E-IRwireRBulb =120V-15.0 A×0.400 Ω192 Ω =0.59 A

Finally, power in the bulb with motor on is:

P2=I22Rb =0.59 A2×192 Ω =66.8 W

Therefore, the power will the bulb dissipate if a total of 15.0 A passes through the wires when the motor comes on is 66.8 W.

Step 3: Power consumed by motor

(b)

To calculate power consumed by the motor we need to calculate current going through the motor:

I3=I-I2 =15.0 A-0.59A =14.41 A

Next, resistance of the motor can be calculated as:

Rm=E-IR1I3 =120V-15.0 A×0.400 Ω14.41 A =7.92 Ω

Finally, power of the motor is:

Pm=I32Rm =14.41A2×7.92 Ω =1644 W

Hence, the power consumed by motor is 1644 W.

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.