Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

If the electric field lines in the figure above were perpendicular to the object, would it necessarily be a conductor? Explain.

When electric field lines are perpendicular to the object, the object must be a conductor.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Gauss law

Gauss stated that the electric flux $φ$ through a hypothetical Gaussian surface equals to $\frac{1}{ε_{\circ}}$ times of the total charge enclosed inside the hypothetical Gaussian surface. Mathematically,

$φ = \frac{q_{e n c}}{ε_{\circ}} . . . . . . . . . . (1.1)$

Here, $q_{e n c}$ is the charge enclosed inside the Gaussian surface, and $ε_{\circ}$ is the permittivity of the free space.

Step 2: Electric field on the surface of the conductor

When some charge is given to the conductor, the charge distributes itself on the surface of the conductor in order to reduce the repulsion between them. This mutual repulsion can only be minimized if there is no component of the field that is applying force on other charges. This is only possible if the field lines are perpendicular to the surface charge distribution.

Thus. The electric field for a conductor is perpendicular to its surface.

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College Physics (Urone)

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Short Answer

If the electric field lines in the figure above were perpendicular to the object, would it necessarily be a conductor? Explain.

Step by Step Solution

Step 1: Gauss law

Step 2: Electric field on the surface of the conductor

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College Physics (Urone)

Answers without the blur.

Short Answer

If the electric field lines in the figure above were perpendicular to the object, would it necessarily be a conductor? Explain.

Step by Step Solution

Step 1: Gauss law

Step 2: Electric field on the surface of the conductor

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