Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


College Physics (Urone)
Found in: Page 667

Answers without the blur.

Just sign up for free and you're in.


Short Answer

(a) Calculate the electric field strength near a 10.0 cm diameter conducting sphere that has 1.00 C of excess charge on it. (b) What is unreasonable about this result? (c) Which assumptions are responsible?

(a) The strength of the electric field is 3.6×1012N/C . (b) The field is too large to be in air. (c) 1.00 charge is excessive.

See the step by step solution

Step by Step Solution

Step 1: Given Data

  • Diameter of a sphere is 10.0 cm
  • Charge on sphere is 1.00 C

Step 2: Electric field

The electric field is defined as the force experienced by a unit positive test charge due to the presence of another charge. The expression for the electric field is,


Here, F is the electrostatic force and q is the test charge.

Step 3: (a) Strength of the electric field

The formula for electric field strength is,


Here, K is the electrostatic force constant, q is the charge on the conducting sphere, and d is the diameter of the sphere.

Substitute K=9×109N-m2/C2 , q=1.00 C , d=10.0 cm,

role="math" localid="1653734461721" E=9×109N-m2/C2×1.00 C10.0 cm22 =9×109N-m2/C2×1.00 C10.0 cm2×10-2m1 cm2 =3.6×1012N/C

Hence, the value of the electric field strength is 3.6×1012N/C .

Step 4: (b) Unreasonable about the result

The dielectric breakdown occurs at 3×106 N/C , which is much less than the field outside this sphere. Sparks would occur before reaching the field strength of 3.6×1012 N/C .

Hence, the field is too large to be in air.

Step 5: (c) Responsible assumptions

The responsible assumption is that, the 1.00 C charge is excessive.

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.