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Q8PE

Expert-verifiedFound in: Page 664

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**What net charge would you place on a 100 g piece of sulfur if you put an extra electron on 1 in 10 ^{12} of its atoms? (Sulfur has an atomic mass of 32.1.)**

If sulfur has an extra 1 electron in 10^{12} of its atoms, then the net charge on 100 g piece is $-0.300\mu C$.

- Mass of piece of sulphur is 100 g
- Fraction of extra electrons is $\frac{1}{{10}^{12}}$

- Atomic mass of sulphur is 32.1

When there is imbalance in the number of electron and proton in a body, then it is said to be charged. If a body gains extra electron, the body is said to be negatively charged.

The number of moles of sulfur is,

$N=\frac{m}{M}$

Here, *N* is the number of moles of sulfur, *m* is the mass of the sulfur piece (*m* = 100 g) , and is the molar mass of the sulfur ( *M* = 32.1 g ) .

Substituting all known values,

$N=\frac{100g}{32.1g}\phantom{\rule{0ex}{0ex}}=3.115$

The number of sulfur atom is,

${N}_{a}=\left(3.115\right)\times \left(6.022\times {10}^{23}\right)\phantom{\rule{0ex}{0ex}}=1.876\times {10}^{24}$

Since, there is 1 extra electron on every 10^{12} atom. Therefore, the number of extra electrons is,

$n=\frac{1.876\times {10}^{24}}{{10}^{12}}\phantom{\rule{0ex}{0ex}}=1.876\times {10}^{12}$

According to the quantization of charge,

Q = ne

Here, Q is the net charge, *n* is the number of extra electron $\left(n=1.876\times {10}^{12}\right)$ , and *e* is the charge on an electron $\left(e=-1.6\times {10}^{-19}\mathrm{C}\right)$ .

Substituting all known values,

$Q=\left(1.876\times {10}^{12}\right)\times \left(-1.6\times {10}^{-19}C\right)\phantom{\rule{0ex}{0ex}}=3.00\times {10}^{-7}C\times \left(\frac{1\mu C}{{10}^{-6}C}\right)\phantom{\rule{0ex}{0ex}}=-0.300\mu C$

Hence, the net charge on 100 g of piece of sulfur, if it has an extra 1 electron in 10^{12} of its atoms, is $-0.300\mu C$ .

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