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Q14CQ

Expert-verifiedFound in: Page 731

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**The power dissipated in a resistor is given by ${\mathit{P}}{\mathbf{=}}{{\mathit{V}}}^{{\mathbf{2}}}{\mathbf{/}}{\mathit{R}}$****, which means power decreases if resistance increases. Yet this power is also given by ${\mathit{P}}{\mathbf{=}}{{\mathit{I}}}^{{\mathbf{2}}}{\mathit{R}}$, which means power increases if resistance increases. Explain why there is no contradiction here.**

There is no contradiction because $V$and $I$ are not always constants and are dependent on one another.

**In an electrical circuit, resistance is a measure of the resistance to current **

**flow. The Greek letter omega (Ω) is used to represent resistance in ohms.**

There is no inconsistency because $V$and $I$ are not always constants and are dependent on one another.

By Ohm's law,

$V=IR$

$V$ , $I$ , and $R$ are connected to each other.

It is possible to convert one power equation to another.

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