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College Physics (Urone)
Found in: Page 733
College Physics (Urone)

College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

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Short Answer

What is the effective resistance of a car’s starter motor when \({\bf{150}}\;{\bf{A}}\) flows through it as the car battery applies \({\bf{11}}{\bf{.0}}\;{\bf{V}}\) to the motor?

The effective resistance of the car’s starter motor is \(0.073\;{\rm{\Omega }}\).

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Identification of the given data

The given data can be listed below as,

  • The value of current flow is, \(I = 150\;{\rm{A}}\).
  • The potential difference of the battery is, \(V = 11.0\;{\rm{V}}\).

Step 2: Significance of the Ohm’s law 

According to Ohm's law, the value of potential difference across a specific electrical circuit is directly proportional to the electrical current flow. The proportionality constant in this relationship is the circuit element's resistance.

Step 3: Determination of the effective resistance of the car’s starter motor

The expression to calculate the effective resistance of the car’s starter motor is expressed as,

\(\begin{align}V = IR\\R = \frac{V}{I}\end{align}\)

Here, \(R\) is the effective resistance of the car’s starter motor.

Substitute all the known values in the above equation.

\(\begin{align}R = \left( {\frac{{11.0\;{\rm{V}}}}{{150\;{\rm{A}}}}} \right)\\ \approx 0.0733\;{\rm{V/A}}\\ \approx \left( {0.0733\;{\rm{V/A}}} \right)\left( {\frac{{1\;{\rm{\Omega }}}}{{1\;{\rm{V/A}}}}} \right)\\ \approx 0.073\;{\rm{\Omega }}\end{align}\)

Thus, the effective resistance of the car’s starter motor is \(0.073\;{\rm{\Omega }}\).

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