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Found in: Page 735

### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

# A total of $${\bf{600}}\;{\bf{C}}$$ of charge passes through a flashlight in$${\bf{0}}{\bf{.500}}\;{\bf{h}}$$. What is the average current?

The value of the average current is $$0.333\;{\rm{A}}$$.

See the step by step solution

## Step 1: Identification of the given data

The given data can be listed below as,

• The total electric charge is, $$Q = 600\;{\rm{C}}$$.
• The time interval is, $$t = 0.500\;{\rm{h}}$$.

## Step 2: Significance of average electric current

The value of the average current can be calculated from the value of the charge quantity that flows in the given time. Generally, the measuring unit of the current is Ampere (A).

## Step 3: Determination of the average electric current

The relation to calculate the average current is expressed as,

\begin{aligned}Q = It\\I = \frac{Q}{t}\end{aligned}

Here, $$I$$ is the average current.

Substitute all the known values in the above equation.

\begin{aligned}I = \left( {\frac{{600\;{\rm{C}}}}{{0.500\;{\rm{h}}}}} \right)\left( {\frac{{\frac{1}{{3600}}\;{\rm{C/s}}}}{{1\;{\rm{C/h}}}}} \right)\left( {\frac{{1\;{\rm{A}}}}{{1\;{\rm{C/s}}}}} \right)\\ \approx 0.333\;{\rm{A}}\end{aligned}

Thus, the average current is$$0.333\;{\rm{A}}$$.