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Q3PE

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College Physics (Urone)
Found in: Page 733

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Short Answer

What is the current when a typical static charge of \({\bf{0}}{\bf{.250}}\;{\bf{\mu C}}\) moves from your finger to a metal doorknob in \({\bf{1}}{\bf{.00}}\;{\bf{\mu s}}\) ?

The value of current moves from finger to metal doorknob is \(0.250\;{\rm{A}}\).

See the step by step solution

Step by Step Solution

Step 1: Identification of the given data

The given data can be listed below as,

  • The value of static electric charge is, \(Q = 0.250\;{\rm{\mu C}}\).
  • The value of time interval is, \(t = 1.00\;{\rm{\mu s}}\).

Step 2: Significance of electric current

An electric current is the flow of electrons when a potential difference is applied between two ends of a wire. When electrons flow through a material of high resistivity, then electrical energy would converts in the heat energy.

Step 3: Determination of the current move from finger to metal doorknob

The relation to calculate the current move from finger to metal doorknob is expressed as,

\(\begin{aligned}Q = It\\I = \frac{Q}{t}\end{aligned}\)

Here, \(I\) is the current move from finger to metal doorknob.

Substitute all the known values in the above equation.

\(\begin{aligned}I = \left( {\frac{{0.250\;{\rm{\mu C}}\; \times \frac{{{{10}^{ - 6}}\;{\rm{C}}}}{{1\;{\rm{\mu C}}}}}}{{1.00\;{\rm{\mu s}}\; \times \frac{{{{10}^{ - 6}}\;{\rm{s}}}}{{1\;{\rm{\mu s}}}}}}} \right)\left( {\frac{{1\;{\rm{A}}}}{{1\;{\rm{C/s}}}}} \right)\\ = 0.250\;{\rm{A}}\end{aligned}\)

Thus, the current move from finger to metal doorknob is \(0.250\;{\rm{A}}\).

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