Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

Answers without the blur.

Just sign up for free and you're in.

Short Answer

What is the capacitance of a large Van de Graaff generator's terminal, given that it stores \(8.00{\rm{ }}mC\)of charge at a voltage of \(12.0{\rm{ }}MV\)?

The capacitance of a large Van de Graaff generator's terminal is \(667{\rm{ }}pF\).

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Defining capacitor

A capacitor is a device used to store electrical energy and works in an electric field. It is a passive electrical component with two terminals. Capacitance is the term used to describe the effect of a capacitor.

Step 2: Work of Capacitor and Information Provided

Any pair of conductors separated by an insulating substance is referred to as a capacitor. When the capacitor is charged, the two conductors have charges of equal magnitude \(Q\) and opposite sign, and the positively charged conductor's potential \(\Delta V\) with respect to the negatively charged conductor is proportional to \(Q\) The ratio of \(Q\) to \(\Delta V\) determines the capacitance \(C\)

\(C = \frac{Q}{{\Delta V}}\)

The farad is the SI unit of capacitance (\(F\)): \(F = 1C/V\)

The Van de Graaff has a charge stored in it.

\(\begin{array}{c}Q = (8.00{\rm{ }}mC)\left( {\frac{{1{\rm{ }}C}}{{{{10}^3}{\rm{ }}\mu C}}} \right)\\ = 8.00 \times {10^{ - 3}}{\rm{ }}C{\rm{ }}\end{array}\)

The Van de Graaff generator's potential difference is

\(\begin{array}{c}V = (12.0\;V)\left( {\frac{{{{10}^6}\;V}}{{1{\rm{ }}mV}}} \right)\\ = 12.0 \times {10^6}\;V\end{array}\)

Step 3: Value of the capacitor

Equation gives the capacitance of the Van de Graaff generator's terminal.

\(C = \frac{Q}{{\Delta V}}\)

Substitute the values of \(Q\) and \(\Delta V\):

\(\begin{array}{c}C = \frac{{8.00 \times {{10}^{ - 3}}{\rm{ }}C}}{{12.0 \times {{10}^6}\;V}}\\ = 6.67 \times {10^{ - 10}}\;F\\ = \left( {667 \times {{10}^{ - 12}}\;F} \right)\left( {\frac{{{{10}^{12}}{\rm{ }}pF}}{{1\;F}}} \right)\\ = 667{\rm{ }}pF\end{array}\)

Therefore, the capacitance needed is \(667{\rm{ }}pF\).

Find Study Materials for

Create Study Materials

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

What is the capacitance of a large Van de Graaff generator's terminal, given that it stores \(8.00{\rm{ }}mC\)of charge at a voltage of \(12.0{\rm{ }}MV\)?

Step by Step Solution

Step 1: Defining capacitor

Step 2: Work of Capacitor and Information Provided

Step 3: Value of the capacitor

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

What is the capacitance of a large Van de Graaff generator's terminal, given that it stores \(8.00{\rm{ }}mC\)of charge at a voltage of \(12.0{\rm{ }}MV\)?

Step by Step Solution

Step 1: Defining capacitor

Step 2: Work of Capacitor and Information Provided

Step 3: Value of the capacitor

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Work Energy and Power

Radiation

Astrophysics

Physics of Motion

Scientific Method Physics

Fluids

Torque and Rotational Motion

Nuclear Physics

Fields in Physics

Measurements

Space Physics

Electricity

Physical Quantities and Units

Medical Physics

Electrostatics

Further Mechanics and Thermal Physics

Mechanics and Materials

Engineering Physics

Energy Physics

Force

Particle Model of Matter

Waves Physics

Magnetism

Modern Physics

Atoms and Radioactivity

Dynamics

Electricity and Magnetism

Conservation of Energy and Momentum

Fundamentals of Physics

Kinematics Physics

Circular Motion and Gravitation

Linear Momentum

Rotational Dynamics

Oscillations

Translational Dynamics

Geometrical and Physical Optics

Thermodynamics

Magnetism and Electromagnetic Induction

Electromagnetism

Electric Charge Field and Potential

Turning Points in Physics