Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

What is the potential $0.530 \times 10^{- 10} m$ from a proton (the average distance between the proton and electron in a hydrogen atom)?

The potential at $0.530 \times 10^{- 10} m$ from a proton is $V = 27.2 V$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given Data

Distance from proton is $0.530 \times 10^{- 10} m$

Step 2: Concept Introduction

Electric Potential Due to a Single Charge: To determine the electric potential V due to a single source charge Q at a specific location, place a test charge q at that location and determine the electric potential energy U_Qq of a system containing the test charge and the source charge that creates the field. The electric potential is given as–

$V = \frac{U_{Qq}}{q} = \frac{kQ}{r} . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)$

Where $k = 8.99 \times 10^{9} N \cdot m^{2} / C$ is a proportionality constant called Coulomb's constant.

Step 3: Calculation for Electric Potential

The electric potential a distance r from the proton is found from Equation (1) –

$V = \frac{kq}{r}$

Entering the values for k, q, and r–

$\begin{array}{rcl} V & = & \frac{(8.99 \times 10^{9} N \times m^{2} / C) (1.60 \times 10^{- 19} C)}{0.530 \times 10^{- 10} m} \\ = & 27.2 V \end{array}$

Therefore, the potential is obtained as $V = 27.2 V$ .

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College Physics (Urone)

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Short Answer

What is the potential $0.530 \times 10^{- 10} m$ from a proton (the average distance between the proton and electron in a hydrogen atom)?

Step by Step Solution

Step 1: Given Data

Step 2: Concept Introduction

Step 3: Calculation for Electric Potential

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College Physics (Urone)

Answers without the blur.

Short Answer

What is the potential 0.530×10-10 m from a proton (the average distance between the proton and electron in a hydrogen atom)?

Step by Step Solution

Step 1: Given Data

Step 2: Concept Introduction

Step 3: Calculation for Electric Potential

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