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Q65PE

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College Physics (Urone)
Found in: Page 699

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Short Answer

A 165 μFcapacitor is used in conjunction with a motor. How much energy is stored in it when 119 V is applied?

The energy stored in the capacitor is 1.17 J.

See the step by step solution

Step by Step Solution

Step 1: Definition of Capacitor

The energy stored in a capacitance C capacitor charged to a potential difference ΔV is as follows:

UE=12C(ΔV)2

Step 2: Given information

The capacitor's capacitance is: C=(165 μF)(1 F106μF)=165×10-6 F

The capacitance's potential difference is: ΔV=119 V

Step 3: Finding the energy  stored in the capacitor

The amount of energy stored in the capacitor can be found from the equation:

UE=12C(ΔV)2

Now, substitute the values of C and V

We get,

UE=12(165×10-6 F)(119 V)2=1.17 J

Therefore, the energy stored in the capacitor is 1.17 J.

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