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Q15PE

Expert-verifiedFound in: Page 860

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**Use Faraday’s law, Lenz’s law, and RHR-1** **to show that the magnetic force on the current in the moving rod in Figure 23.11**** is in the opposite direction of its velocity.**

We found that if the direction of the current is upward, then the force will be towards the left, opposite the velocity.

**An electromotive force is produced in the closed conductor that is placed in a continuously changing magnetic field. The induced emf is such that it opposed the cause due to which the magnetic field is changing. This is known as Electromagnetic induction.**

This question must view the drawing given in the book.

As the moving rod increases the surface enclosed by the circuit, the flux will increase. It means that, according to Lenz's law, the current that will flow will be in the direction to oppose this change in flux. So the induced current will be such that its induced magnetic field will counter the change in flux. It means that it will be out of the plane. This allows us to evaluate, using RHR-2, the direction of the current, which is clockwise. Knowing this, we can apply RHR-1. As the direction of the current is upward and the magnetic field into the plane, then the direction of the force will be opposite to the direction of the velocity.

Therefore, if the direction of the current is upward, then the force will be, opposite to the velocity.

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