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Expert-verifiedWhat capacitance should be used to produce a \(2.00\,{\rm{M\Omega }}\) reactance at \(60.0\,{\rm{Hz}}\)?
The capacitance used to produce a reactance is obtained as, \(1.33\,{\rm{nF}}\).
The given data can be listed below as,
The capacity of a component or circuit to gather and hold energy in the form of an electrical charge is known as capacitance. Devices that store energy include capacitors, which come in a variety of sizes and forms.
The inductive reactance is evaluated using the formula:
\({X_C} = \frac{1}{{2\pi fC}}\)
Solving for the capacity as:
\(C = \frac{1}{{2\pi f{X_C}}}\)
Substitute all the value in the above equation.
\(\begin{aligned} L &= \frac{1}{{2\pi \times 60.0\,{\rm{Hz}} \times 2 \times {{10}^6}\,{\rm{\Omega }}}}\\ &= 1.33\,{\rm{nF}}\end{aligned}\)
Therefore, the capacitance used to produce a reactance is, \(1.33\,{\rm{nF}}\).
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