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Expert-verified Found in: Page 888 ### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000 # During normal beating, the heart creates a maximum 4.00-m V potential across 0.300 m of a person’s chest, creating a 1.00 Hz electromagnetic wave. (a) What is the maximum electric field strength created? (b) What is the corresponding maximum magnetic field strength in the electromagnetic wave? (c) What is the wavelength of the electromagnetic wave?

(a) Electric field strength is $1.33×{10}^{-2}V/m$.

(b) Magnetic field strength is $4.43×{10}^{-11}T$.

(c) The wavelength is $3×{10}^{8}m$.

See the step by step solution

## Step 1: Define electromagnetic waves

Electromagnetic waves are waves that are produced by changes in the electric and magnetic fields.

## Step 2: Evaluating maximum electric field strength(a)

The strength of an electric field may be stated in terms of potential difference and distance using the formula:

$E=\frac{V}{d}$ ………………(1)

Where, E is electric field, V is potential difference and d is distance.

Substitute the values in the equation (1), we get

$E=\frac{4×{10}^{-3}V}{0.3m}\phantom{\rule{0ex}{0ex}}=1.33×{10}^{-2}V/m$

Therefore, electric field strength is $1.33×{10}^{-2}V/m$.

## Step 3: Evaluating maximum magnetic field strength(b)

The formula describing the relationship between magnetic field, electric field, and light speed is:

$B=\frac{E}{c}$ …………….(2)

Where, B is magnetic field, E is electric field and c is light speed.

Substitute the values,

$B=\frac{1.33×{10}^{-2}V/m}{3×{10}^{8}m/s}\phantom{\rule{0ex}{0ex}}=4.43×{10}^{-11}V.s/{m}^{2}\phantom{\rule{0ex}{0ex}}=4.43×{10}^{-11}T$

Therefore, magnetic field strength is $4.43×{10}^{-11}T$

## Step 4: Evaluating wavelength(c)

The frequency of light and its speed are known to be connected by a formula.

$\lambda =\frac{c}{f}$ …………………(3)

Where, $\lambda$ is wavelength, c is light speed and f is frequency.

Substitute the values,

$\lambda =\frac{3×{10}^{8}m/s}{1Hz}\phantom{\rule{0ex}{0ex}}=3×{10}^{8}m$

Therefore, the wavelength is $3×{10}^{8}m$. ### Want to see more solutions like these? 