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Q20PE

Expert-verifiedFound in: Page 888

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**During normal beating, the heart creates a maximum 4.00-m V ****potential across 0.300 m ****of a person’s chest, creating a 1.00 Hz ****electromagnetic wave. (a) What is the maximum electric field strength created? (b) What is the corresponding maximum magnetic field strength in the electromagnetic wave? (c) What is the wavelength of the electromagnetic wave?**

(a) Electric field strength is $1.33\times {10}^{-2}V/m$.

(b) Magnetic field strength is $4.43\times {10}^{-11}T$.

(c) The wavelength is $3\times {10}^{8}m$.

**Electromagnetic waves are waves that are produced by changes in the electric and magnetic fields.**

The strength of an electric field may be stated in terms of potential difference and distance using the formula:

$E=\frac{V}{d}$ ………………(1)

Where, E is electric field, V is potential difference and d is distance.

Substitute the values in the equation (1), we get

$E=\frac{4\times {10}^{-3}V}{0.3m}\phantom{\rule{0ex}{0ex}}=1.33\times {10}^{-2}V/m$

Therefore, electric field strength is $1.33\times {10}^{-2}V/m$.

The formula describing the relationship between magnetic field, electric field, and light speed is:

$B=\frac{E}{c}$ …………….(2)

Where, B is magnetic field, E is electric field and c is light speed.

Substitute the values,

$B=\frac{1.33\times {10}^{-2}V/m}{3\times {10}^{8}m/s}\phantom{\rule{0ex}{0ex}}=4.43\times {10}^{-11}V.s/{m}^{2}\phantom{\rule{0ex}{0ex}}=4.43\times {10}^{-11}T$

Therefore, magnetic field strength is $4.43\times {10}^{-11}T$

The frequency of light and its speed are known to be connected by a formula.

$\lambda =\frac{c}{f}$ …………………(3)

Where, $\lambda $ is wavelength, c is light speed and f is frequency.

Substitute the values,

$\lambda =\frac{3\times {10}^{8}m/s}{1Hz}\phantom{\rule{0ex}{0ex}}=3\times {10}^{8}m$

Therefore, the wavelength is $3\times {10}^{8}m$.

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