Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

A scuba diver training in a pool looks at his instructor as shown in Figure 25.53. What angle does the ray from the instructor’s face make with the perpendicular to the water at the point where the ray enters? The angle between the ray in the water and the perpendicular to the water is $25 . 0^{°}$ .

The $34 . 3^{°}$ angle does the ray from the instructor’s face make with the perpendicular to the water at the point where the ray enters.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Concept Introduction

An angle is created by two rays, called the sides of the angle. They share a common end point, called the vertex of the angle, in Euclidean geometry. Angles generated by two rays lie in the plane in which the rays are contained.

Step 2: Calculating the angle

Using Snell's law of refraction, $n_{i} \sin θ_{i} = n_{f} \sin θ_{f}$ we need to solve for the angle of refraction

$θ_{f} = \sin^{- 1} (\frac{n_{i} \sin θ_{i}}{n_{f}}) = \sin^{- 1} (\frac{1.333 \times \sin 25^{°}}{1.000}) = 34 . 3^{°}$

Therefore, the required solution is $34 . 3^{°}$ .

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College Physics (Urone)

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Step 1: Concept Introduction

Step 2: Calculating the angle

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College Physics (Urone)

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Short Answer

A scuba diver training in a pool looks at his instructor as shown in Figure 25.53. What angle does the ray from the instructor’s face make with the perpendicular to the water at the point where the ray enters? The angle between the ray in the water and the perpendicular to the water is 25.0°.

Step by Step Solution

Step 1: Concept Introduction

Step 2: Calculating the angle

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