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Q15PE

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College Physics (Urone)
Found in: Page 11

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Short Answer

(a) Suppose that a person has an average heart rate of 72.0 beats/min beats/ min. How many beats does he or she have in 2.0 y ? (b) In 2.00 y ? (c) In 2.000 y ?

  1. In 2.0 years , there are only 2 significant figures. Hence, the number of beats is 7.6×107 beats.
  2. In 2.0 years , since there are 3 significant figures. Hence, the number of beats is 7.57×107 beats.
  3. There are 4 significant figures in 2,000 years, the 72.0 beats/min only has 3 significant figures, so report the answer with 3 significant figures i.e., 7.573×107 beats .
See the step by step solution

Step by Step Solution

Step 1: Definition of conversion factor

A conversion factor that determines how many units are equal to a unit.

Given Data:

Consider the given data as below.

Average heart rate is 72.0 beats/min .

Step 2: Calculating total beats

  1. Multiply 72.0 beats/min by 2.0 years for calculating the number of beats she has in 2.0 years and hence after that use conversion factors to cancel the units of time.

Numbers of beats =72 beats1 min×60 min1 hr×24 hr1 day×365 days1 yr×2 years =7.57382×107 beats

In 2.0 years , there are only 2 significant figures. Hence, the number of beats is 7.6×107 beats.

(b) In 2.0 years , since there are 3 significant figures. Hence, the number of beats is 7.57×107 beats.

(c) Here, there are 4 significant figure in 2,000 years , the 72.0 beats/min only has 3 significant figures, so report the answer with 3 significant figures i.e., 7.573×107 beats.

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