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Q5PE

Expert-verifiedFound in: Page 11

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**Soccer fields vary in size. A large soccer field is 115 m **** long and 85 m **** wide. What are its dimensions in feet and inches? (Assume that 1 meter equals 3.281 feets****).**

The dimension for length in feet is 377.2 ft and 278.8 ft respectively.

The dimension for width in inches is 4527.55 and 3346.45 inch -respectively.

**The length of a figure, which is its longest dimension, indicates how long an item or figure is. Linear units such as meters, centimeters, inches and other measurements are used to convey it. **

**The shorter distance of an item or a figure is its width, which indicates how wide or broad the provided figure is.**

Consider the given data as below.

Length of the soccer field, I = 115 m

Width of the soccer field, w = 85 m

$1\mathrm{meter}=3.28\mathrm{foot}\phantom{\rule{0ex}{0ex}}1\mathrm{meter}=39.37\mathrm{inch}$

The length of the soccer field,-

$\mathrm{I}=115\mathrm{m}\times \frac{3.28\mathrm{ft}}{1\mathrm{m}}\phantom{\rule{0ex}{0ex}}=377.2\mathrm{ft}$

The width of the soccer field,-

$\mathrm{w}=85\mathrm{m}\times \frac{3.28\mathrm{ft}}{1\mathrm{m}}\phantom{\rule{0ex}{0ex}}=278.8\mathrm{ft}$

Hence, the dimension for length in feet is 377.2 ft and 278.8 ft respectively.

The length of the soccer field,-

$\mathrm{I}=115\mathrm{m}\times \frac{39.37\mathrm{inch}}{1\mathrm{m}}\phantom{\rule{0ex}{0ex}}=4527.55\mathrm{inch}$

The width of the soccer field

$\mathrm{w}=85\mathrm{m}\times \frac{39.37\mathrm{inch}}{1\mathrm{m}}\phantom{\rule{0ex}{0ex}}=3346.45\mathrm{inch}$

Hence, the dimension for width in inches is $4527.55\mathrm{inch}$ and $3346.45\mathrm{inch}$ respectively.

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