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Q8PE

Expert-verifiedFound in: Page 33

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**The speed of sound is measured to be **\({\rm{342 }}{{\rm{m}} \mathord{\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. \\} {\rm{s}}}\)** ****on a certain day. What is this in km/h?**

** **

Hence, the speed of sound is \(1231.2{\rm{ }}{{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\).

**Meter is a SI unit of distance. It is abbreviated as a meter. **

The relation between kilometers and meters is given as

\(1{\rm{ }}kilometer = 1000{\rm{ }}meters\)

**Given data**

Consider the given data as below.

The speed of sound =\(342{\rm{ }}{m \mathord{\left/ {\vphantom {m s}} \right. \\} s}\)

The value of speed of sound in km/h can be expressed through conversion.

Converting 1 sec to 1 hour

\({1 \mathord{\left/ {\vphantom {1 {3600}}} \right.\\} {3600}} = 0.000277778{\rm{ }}hours\)

Therefore, we can imply 1m/sec

\(\begin{aligned}{}1{\rm{ }}{m \mathord{\left/ {\vphantom {m s}} \right. \\} s} = {\raise0.7ex\hbox{${{{10}^{ - 3}}{\rm{ }}km}$} \!\mathord{\left/ {\vphantom {{{{10}^{ - 3}}{\rm{ }}km} {0.00027778{\rm{ }}hour}}}\right.\\}\!\lower0.7ex\hbox{${0.00027778{\rm{ }}hour}$}}\\ = 599.99\times {10^{ - 3}}{\rm{ }}{{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\end{aligned}\)\(342{\rm{ }}{m \mathord{\left/ {\vphantom {m s}} \right. \\} s} = 3599.99 \times {10^{ - 3}}{\rm{ }}{{km} \mathord{\left/ {\vphantom{{km} {hr}}} \right. \\} {hr}}\)

Therefore,\(1{\rm{ }}{m \mathord{\left/ {\vphantom {m s}} \right. \\} s} = 3.6{\rm{ }}{{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\)

So, the velocity will be,

\(3.6{\rm{ }}x{\rm{ }}342 = 1231.2{\rm{ }}{{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\)

Hence, the speed of sound in \({{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\) is \(1231.2{\rm{ }}{{km} \mathord{\left/ {\vphantom {{km} {hr}}} \right. \\} {hr}}\).

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