Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot takes\({\bf{3}}{\bf{.33 \times 1}}{{\bf{0}}^{{\bf{ - 2}}}}\;{\bf{s}}\), calculate the distance over which the puck accelerates.

The distance for acceleration of puck is \(0.8\;{\rm{m}}\).

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TABLE OF CONTENTS :

TABLE OF CONTENTS

Determination of acceleration of puck

Given Data:

The initial velocity of racer is \(u = 8\;{\rm{m}}/{\rm{s}}\)

The final velocity of racer is \(v = 40\;{\rm{m}}/{\rm{s}}\)

The time for acceleration of slap shot is \(t = 3.33 \times {10^{ - 2}}\;{\rm{s}}\)

The distance travelled by puck is found by first calculating the acceleration by first equation of motion and then applying the third equation of motion.

The acceleration of the puck is given as

\(v = u + at\)

Here, \(a\) is the deceleration of the puck.

Substitute all the values in the above equation.

\(\begin{array}{c}40\;{\rm{m}}/{\rm{s}} = 8\;{\rm{m}}/{\rm{s}} + a\left( {3.33 \times {{10}^{ - 2}}\;{\rm{s}}} \right)\\a = 961\;{\rm{m}}/{{\rm{s}}^2}\end{array}\)

Determination of distance for acceleration of puck

The distance for acceleration of the puck is given as

\({v^2} = {u^2} + 2ad\)

Substitute all the values in the above equation.

\[\begin{array}{c}{\left( {40\;{\rm{m}}/{\rm{s}}} \right)^2} = {\left( {8\;{\rm{m}}/{\rm{s}}} \right)^2} + 2\left( {961\;{\rm{m}}/{{\rm{s}}^2}} \right)d\\d = 0.8\;{\rm{m}}\end{array}\]

Therefore, the distance for acceleration of the puck is \(0.8\;{\rm{m}}\).

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College Physics (Urone)

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Short Answer

In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot takes\({\bf{3}}{\bf{.33 \times 1}}{{\bf{0}}^{{\bf{ - 2}}}}\;{\bf{s}}\), calculate the distance over which the puck accelerates.

Step by Step Solution

Determination of acceleration of puck

Determination of distance for acceleration of puck

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College Physics (Urone)

Answers without the blur.

Short Answer

In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. If this shot takes\({\bf{3}}{\bf{.33 \times 1}}{{\bf{0}}^{{\bf{ - 2}}}}\;{\bf{s}}\), calculate the distance over which the puck accelerates.

Step by Step Solution

Determination of acceleration of puck

Determination of distance for acceleration of puck

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