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### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

# During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of $$10.0kg$$and the horizontal component of its velocity is $$8.00 m/s$$when the $$65.0kg$$performer catches it. If the performer is on nearly frictionless roller skates, what is his recoil velocity?

The velocity of the system after collision will be $$1.07 m/s$$.

See the step by step solution

## Step 1: Definition of collision

According to collision theory, only a specific number of collisions between acceptable reactant particles with the correct orientation result in a detectable or noticeable change; these successful modifications are referred to as successful collisions.

## Step 2: Given data

The velocity of cannon ball is $${v_c} = 8.00 m/s$$in right side.

The mass of the cannon ball is$${M_c} = 10.0kg$$.

The velocity of the person is$${v_p} = 0$$

The mass of the person is$${M_p} = 65kg$$

The Collison is inelastic.

## Step 3: Velocity of the system of players after the collision

By putting all the value into the equation we get

\begin{aligned}{M_c}{V_c} + {M_p}{V_p} &= + {M_T}{V_f}\\{V_f} &= \dfrac{{{M_v}{V_c} + {M_p}{V_p}}}{{{M_T}}}\\{V_f} &= \dfrac{{\left( {10} \right)\left( 8 \right) + \left( {65} \right)\left( 0 \right)}}{{\left( {10 + 65} \right)}}\\{V_f} &= 1.07\,m/s\end{aligned}…………………(1)

Hence the velocity of the system after collision will be$$1.07 m/s$$. They will move towards right side as the velocity answer is positive.