Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

(a) What is the speed of a supersonic aircraft with a $17.0 ‐ m$ wingspan, if it experiences a $1.60 ‐ V$ Hall voltage between its wing tips when in level flight over the north magnetic pole, where the Earth’s field strength is $8.00 \times 10^{‐ 5} T$ (b) Explain why very little current flows as a result of this Hall voltage.

(a) The speed of the aircraft is $1.17 \times 10^{3} m / s$ .

(b) The little number of current flows is a result of this Hall voltage as there exists a magnetic force pushing the charges in the opposite direction.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given information

The wingspan of the supersonic aircraft is $L = 17.0 m$

The magnetic field strength of the earth is $B = 8.00 \times 10^{‐ 5} T$

Induced voltage due to the Hall effect is $E = 1.60 V$

Step 2: Define the Hall effect

An induced voltage generated by a charge carrier moving in an applied magnetic field perpendicular to the direction of motion can be expressed as,

$E = BLv$ …………………(1)

Step 2: Evaluating the hall voltage

Substitute the given data in equation (1) to evaluate the speed that produces such hall voltage can be given as,

$v = \frac{E}{BL} = \frac{1.60 V}{(8.00 \times 10^{‐ 5} T) \times (17.0 m)} = 1.17 \times 10^{3} m / s$

Therefore the speed of supersonic aircraft is $1.17 \times 10^{3} m / s$ .

Step 3: Explanation of why little current flow as a result of this hall voltage

(b)

Very little current flows as a result of this Hall voltage due to the reason that there exists a magnetic force that pushes the charges in the opposite direction.

Therefore, the flow of a small current is due to the Hall voltage as there already exists a magnetic force pushing the charges in the opposite direction.

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College Physics (Urone)

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Short Answer

Step by Step Solution

Step 1: Given information

Step 2: Define the Hall effect

Step 2: Evaluating the hall voltage

Step 3: Explanation of why little current flow as a result of this hall voltage

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College Physics (Urone)

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Short Answer

Step by Step Solution

Step 1: Given information

Step 2: Define the Hall effect

Step 2: Evaluating the hall voltage

Step 3: Explanation of why little current flow as a result of this hall voltage

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