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College Physics (Urone)
Found in: Page 811
College Physics (Urone)

College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

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Short Answer

Repeat Exercise 22.1 for a negative charge.

(a) The direction of the force will be to the right (towards east).

(b) The direction of the force will be outside of the page (outwards or towards you).

(c) The direction of the force will be downwards (towards the south).

(d) No force.

(e) The direction of the force will be to the left (towards the west).

(f) The direction of the force will be upwards (towards north).

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Definition of right-hand thumb rule.

The strategy to solve such problems with negative charges is assuming that the charge is positive, getting the direction of the force by the right-hand rule, after that we reverse the direction we got.

In summary, we will reverse every direction we got in the previous question.

Step 2: Explanation of the direction of magnetic force.

(a)

By having the movement pointing down and the magnetic field pointing on the page, the force will be pointing to the left.

(b)

By having the movement pointing up and the magnetic field pointing to the left, the force will be pointing to the outside of the page or towards you.

(c)

By having the movement pointing to the left and the magnetic field pointing into the page, the force will be pointing to the south (downwards).

(d)

By having the movement pointing to the left and the magnetic field pointing to the right, the force will be zero (they are parallel and which will give sin00=0, and therefore force will be zero).

(e)

By having the movement pointing into the page and the magnetic field pointing upward, the force will be pointing to the left in the west direction.

(f)

By having the movement pointing out of the page and the magnetic field pointing to the left, the force will be pointing to the north (upwards).

Most popular questions for Physics Textbooks

Figure 22.62 shows a long straight wire just touching a loop carrying a current I1 . Both lie in the same plane.

(a) What direction must the current l2in the straight wire have to create a field at the center of the loop in the direction opposite to that created by the loop?

(b) What is the ratio of l1/l2 that gives zero field strength at the center of the loop?

(c) What is the direction of the field directly above the loop under this circumstance?

(a) What is the speed of a supersonic aircraft with a 17.0‐m wingspan, if it experiences a 1.60‐V Hall voltage between its wing tips when in level flight over the north magnetic pole, where the Earth’s field strength is 8.00×10‐5 T (b) Explain why very little current flows as a result of this Hall voltage.

The wire carrying 400A to the motor of a commuter train feels an attractive force of 4.00×10-3 N/m due to a parallel wire carrying 5.00 A to a headlight. (a) How far apart are the wires? (b) Are the currents in the same direction?

What is the maximum force on an aluminum rod with a 0.100-µC charge that you pass between the poles of a 1.50-T permanent magnet at a speed of 5.00 m/s? In what direction is the force?

A surveyor \({\rm{100 m}}\) from a long straight \({\rm{200}}\;{\rm{kV}}\) DC power line suspects that its magnetic field may equal that of the Earth and affect compass readings. (a) Calculate the current in the wire needed to create a \({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{ T}}\) field at this distance. (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?
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