Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


College Physics (Urone)
Found in: Page 813

Answers without the blur.

Just sign up for free and you're in.


Short Answer

(a) What is the maximum torque on a 150-turn square loop of wire 18.0 cm on a side that carries a 50.0-A current in a 1.60-T field? (b) What is the torque when θ is 10.9º?

(a) The maximum torque is 360 Nm.

(b) When θ=10.9° , the torque equals 68.1 Nm.

See the step by step solution

Step by Step Solution

Step 1: Definition of Torque.

Torque can be a force applied on the different current carrying loops/segments in a uniform magnetic field.

The torque can be estimated using the expression,

τ=NIABsin(θ) ………………(1)

where the number of turns, N , the current, I , the area of the loop, A , and the inclination angle of the loop, θ .

Step 2: Finding the maximum torque(a)

The maximum torque can be obtained when θ=90° .

The area of the current-carrying loop is,

A=0.18 m×0.18 m =0.03 m2

This can be used in equation (1) to determine the torque, such that,

πmax=NIABsin90° =150×50A×0.03m2×1.60 T×sin90° =360 Nm

Therefore, the maximum torque is 360 Nm.

Step 4: Finding the torque when the angle is (b)

Substitute the given data in equation (1), to determine the torque,

πmax=NIABsin90° =150×50A×0.03m2×1.60 T×sin10.9° =68.1 Nm

Hence, the value of torque is 68.1 Nm.

Most popular questions for Physics Textbooks


Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.