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College Physics (Urone)
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Short Answer

A proton has a magnetic field due to its spin on its axis. The field is similar to that created by a circular to that created by a circular current loop 0.650×1015 m in radius with a current by a circular of 1.05×104A (no kidding ). Find maximum torque on a proton in a 2.50-T field. (This is a significant torque on a small particle.)

The maximum torque on a proton is 3.49×1025 NM.

See the step by step solution

Step by Step Solution

Step 1:Definition of torque

Torque can be defined as the force acting on a current-carrying loop in a uniform magnetic field, which helps to rotate it in the circular orbit.

Step 2: Finding the torque

First of all, we will get the area of the circular loop then we will use the equation τ=IAB to get the maximum torque for the angle to be 90o.

Step 3: Finding the maximum torque

The area is given by,

A=πr2 =π×0.650×1015 m2 =1.33×1030 m2

The formula for the maximum torque is,

τ=IAB =1.05×104 A×1.33×1030 M2×2.50 T =3.49×1026 Nm

Therefore, the maximum torque on a proton is 3.49×1026 NM

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