Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

A proton has a magnetic field due to its spin on its axis. The field is similar to that created by a circular to that created by a circular current loop $0.650 \times 10^{‐ 15}$ m in radius with a current by a circular of $1.05 \times 10^{4}$ A (no kidding ). Find maximum torque on a proton in a 2.50-T field. (This is a significant torque on a small particle.)

The maximum torque on a proton is $3.49 \times 10^{‐ 25} N ‐ M$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1:Definition of torque

Torque can be defined as the force acting on a current-carrying loop in a uniform magnetic field, which helps to rotate it in the circular orbit.

Step 2: Finding the torque

First of all, we will get the area of the circular loop then we will use the equation $τ = IAB$ to get the maximum torque for the angle to be 90o.

Step 3: Finding the maximum torque

The area is given by,

$A = {πr}^{2} = π \times {(0.650 \times 10^{‐ 15} m)}^{2} = 1.33 \times 10^{‐ 30} m^{2}$

The formula for the maximum torque is,

$τ = IAB = (1.05 \times 10^{4} A) \times (1.33 \times 10^{‐ 30} M^{2}) \times 2.50 T = 3.49 \times 10^{‐ 26} N ‐ m$

Therefore, the maximum torque on a proton is $3.49 \times 10^{‐ 26} N ‐ M$

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College Physics (Urone)

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Short Answer

Step by Step Solution

Step 1:Definition of torque

Step 2: Finding the torque

Step 3: Finding the maximum torque

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College Physics (Urone)

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Short Answer

Step by Step Solution

Step 1:Definition of torque

Step 2: Finding the torque

Step 3: Finding the maximum torque

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