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Q48PE

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College Physics (Urone)
Found in: Page 813

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Short Answer

A 200-turn circular loop of radius 50.0 cm is vertical, with its axis on an east-west line. A current of 100 A circulates clockwise in the loop when viewed from the east. The Earth's field here is due north, parallel to the ground, with a strength of 3.00×105 T . What are the direction and magnitude of the torque on the loop? (b) Does this device have any practical applications as a motor?

(a) Torque on the loop is 0.47 Nm.

(b) The torque is very small so the loop will not have any practical applications as a motor.

See the step by step solution

Step by Step Solution

Step 1:  Definition of torque

Torque, also known as force moment, is the tendency of a force to spin the body to which it is applied.

Step2: To get the torque

First,

We will get the area of the circular loop then we will use the equation

τ=NIABsinθ………………….(1)

As the loop is vertical and the magnetic field is pointing to the north, the angle θ=90° that leads to the value of sin90°=1.

Therefore using equation (1), we can write the maximum value of torque such that,

τmax=NIAB……………………..(2)

Step 3: Finding the direction of the torque (a)

The area of the loop can be estimated as,

A=πr2 =π×0.50 m2 =0.79 m2

Then using equation (2), we will determine the torque such that,

τmax=200×100A×0.79m23.00×105T =0.47 Nm

As the current in the loop circulates clockwise and the field points to the north, the torque's direction will be clockwise as well.

Step 4: Does this device have any practical applications as a motor?(b)

The torque is very small so the loop will not have any practical applications as a motor.

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