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Expert-verified Found in: Page 813 ### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000 # Repeat Exercise 22.41 but with the loop lying flat on the ground with its current circulating counterclockwise (when viewed from above) in a location where the Earth's field is north, but at an angle ${\mathbf{45}}{\mathbf{°}}$ below the horizontal and with a strength of${\mathbf{6}}{\mathbf{.}}{\mathbf{00}}{\mathbf{×}}{{\mathbf{10}}}^{\mathbf{‐}\mathbf{5}}{\mathbf{}}{\mathbf{T}}$ .

(a) Maximum torque on a loop is $0.67\mathrm{N}‐\mathrm{m}$ and direction is west.

(b) The torque is very small so the loop will not have any practical application as a motor.

See the step by step solution

## Step 1: Definition of torque

Torque, also known as force moment, is the tendency of a force to spin the body to which it is applied in physics.

We can use the equation to determine the torque,

${\mathbf{\tau }}{\mathbf{=}}{\mathbf{NIABsin}}\left(\theta \right)$ ………….(1)

## Step 2: Finding the torque using the formula(a)

Substitute the values in the equation (1), and we get

$\mathrm{\tau }=200×100\mathrm{A}×0.79{\mathrm{m}}^{2}\left(6.00×{10}^{‐5}\mathrm{T}\right)×\mathrm{sin}\left(45°\right)\phantom{\rule{0ex}{0ex}}=0.67\mathrm{N}‐\mathrm{m}$

Hence, the required maximum torque on a loop is $0.67\mathrm{N}‐\mathrm{m}$

Considering direction of force and current we find that the direction of torque is in west.

## Step 3: Justification (b)

The torque is very small so the loop will not have any practical application as a motor. ### Want to see more solutions like these? 