Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

Inside a motor, 30.0 A passes through a 250 -turn circular loop that is 10.0 cm in radius. What is the magnetic field strength created at its center?

The magnetic field strength calculated is 0.047 T.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1:Given data

The Current inside a motor is $I = 30.0 A \$

The number of turns in the loop is $N = 250 turns$

The radius of the wire is $R = 10.0 cm (\frac{1 m}{100 cm}) = 0.10 m$

Step 2: Determination of magnetic field

The magnetic impact of electric charges in relative motion and magnetized objects is described by a magnetic field, which is a vector field.

The following equation can be used to obtain the magnetic field strength created at the center,

$B = (\frac{{Nμ}_{0} I}{2 R})$ …………………….(1)

Where $N, μ_{0},$ and R are the number of turns, the magnetic permeability of vacuum, and the radius of the wire, respectively.

Step 3: Evaluating the magnetic field

Substitute the given data in equation (1), and we get,

$B = \frac{{Nμ}_{0} I}{2} = \frac{250 \times (4 π \times 10^{- 7} N / m^{2}) \times 30 A}{2 \times 0.10 m} = 0.047 T$

Therefore, the magnetic field strength is 0.047 T.

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College Physics (Urone)

Answers without the blur.

Short Answer

Inside a motor, 30.0 A passes through a 250 -turn circular loop that is 10.0 cm in radius. What is the magnetic field strength created at its center?

Step by Step Solution

Step 1:Given data

Step 2: Determination of magnetic field

Step 3: Evaluating the magnetic field

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College Physics (Urone)

Answers without the blur.

Short Answer

Inside a motor, 30.0 A passes through a 250 -turn circular loop that is 10.0 cm in radius. What is the magnetic field strength created at its center?

Step by Step Solution

Step 1:Given data

Step 2: Determination of magnetic field

Step 3: Evaluating the magnetic field

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