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Q59PE

Expert-verifiedFound in: Page 592

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**Two tuning forks having frequencies of 460 and 464 Hz are struck simultaneously. What average frequency will you hear, and what will the beat frequency be?**

The average frequency of two forks is 462 Hz and beat frequency is 4 Hz.

We calculate beat frequency of two horns as we know that beat frequency is modulus of difference of two frequencies. We also calculate average frequency of two forks.

Frequency of first fork \( = 460 Hz\)

Frequency of second fork \( = 464 Hz\)

Beat frequency \(f = \left| {{f_1} - {f_2}} \right|\)

Average frequency \({f_{avg}} = ({f_1} + {f_2})/2\)

Here,

\({f_1},{f_2}\) - frequency of 2 sources.

\(f\) - beat frequency.

\({f_{avg}} \)-average frequency.

Beat frequency of two forks is

\(\begin{align}{}f &= \left| {{f_1} - {f_2}} \right|\\f &= \left| {460 - 464} \right|Hz\\f &= 4Hz\end{align}\)

Average frequency of two forks is

\(\begin{align}{}{f_{avg}} &= ({f_1} + {f_2})/2\\{f_{avg}} &= (460 + 464)/2\\{f_{avg}} &= 462 Hz\end{align}\)

Therefore, the average frequency of two forks is **462** Hz and beat frequency is **4** Hz.

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