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Q9PE

Expert-verifiedFound in: Page 590

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**Find the frequency of a tuning fork that takes 2.50 x 10 ^{-3} s to complete one oscillation.**

The time taken by the turning fork is, T = 2.50 x 10^{-3} s

The time taken by the turning fork is, T = 2.50 x 10^{-3} s

**The defined period of time for which a particular event occurs at a specific rate is termed the time period. It can be determined by taking the inverse of the frequency and it is measured in terms of seconds.**

Write the expression for the frequency.

\(f = \frac{1}{T}\)

Here, \(T\) is the time period.

Substitute all the values in the above expression.

\(\begin{aligned}f &= \frac{1}{{2.50 \times {{10}^{ - 3}}\;{\rm{s}}}}\\ &= 400\;{{\rm{s}}^{ - 1}} \times \frac{{1\;{\rm{Hz}}}}{{{{\rm{s}}^{ - 1}}}}\\ &= 400\;{\rm{Hz}}\end{aligned}\)

Thus, the frequency is 400 Hz.

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