Suggested languages for you:

Americas

Europe

Q9PE

Expert-verified
Found in: Page 590

### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

# Find the frequency of a tuning fork that takes 2.50 x 10-3 s to complete one oscillation.

The time taken by the turning fork is, T = 2.50 x 10-3 s

See the step by step solution

## Step 1: Identification of the given data

The time taken by the turning fork is, T = 2.50 x 10-3 s

## Step 2: Definition of time period

The defined period of time for which a particular event occurs at a specific rate is termed the time period. It can be determined by taking the inverse of the frequency and it is measured in terms of seconds.

## Step 3: Determination of frequency

Write the expression for the frequency.

$$f = \frac{1}{T}$$

Here, $$T$$ is the time period.

Substitute all the values in the above expression.

\begin{aligned}f &= \frac{1}{{2.50 \times {{10}^{ - 3}}\;{\rm{s}}}}\\ &= 400\;{{\rm{s}}^{ - 1}} \times \frac{{1\;{\rm{Hz}}}}{{{{\rm{s}}^{ - 1}}}}\\ &= 400\;{\rm{Hz}}\end{aligned}

Thus, the frequency is 400 Hz.