Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

Answers without the blur.

Just sign up for free and you're in.

Short Answer

Question: (a) What is the intensity of a sound that has a level \(7.00\;{\rm{dB}}\) lower than a\(4.00 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\)sound? (b) What is the intensity of a sound that is \(3.00\;{\rm{dB}}\)higher than a \(4.00 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\)sound?

The intensity is\(7.94 \times {10^{ - 10}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\).

b. The intensity is\(7.94 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\)

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step1: Given Data

The intensity of a sound has a level \(7.00\;{\rm{dB}}\) lower than a\(4.00 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\).

The intensity of another sound has a level \(3.00\;{\rm{dB}}\) higher than a\(4.00 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\).

Step 2: Loudness

The loudness is the ratio of the sound intensity to the threshold level. It is in the unit of Bel or dB. The loudness refers to the effect of intensity.

Step 3: Calculation of the intensity of the first sound

(a)

Use the intensity of the first sound as ,

\(\begin{align}d &= 10\log \frac{{4.00 \times {{10}^{ - 9}}}}{{{{10}^{ - 12}}}}\\d &= 36\;{\rm{dB}}\end{align}\)

Now the intensity level of the sound is,

\(\begin{align}I &= 36 - 7\\ &= 29\;{\rm{dB}}\end{align}\)

The intensity of the sound is,

\(\begin{align}29 &= 10\log \frac{I}{{{{10}^{ - 12}}}}\\2.9 &= \log \frac{I}{{{{10}^{ - 12}}}}\\I &= {10^{2.9}} \times {10^{ - 12}}\\I &= 7.94 \times {10^{ - 10}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\end{align}\)

The intensity of a sound is \(7.94 \times {10^{ - 10}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\)

Step 4: Calculation of the intensity of the second sound

(b)

Now the intensity level of the sound is,

\(36 + 3 = 39\;{\rm{dB}}\)

The intensity of the sound is,

\(\begin{align}39 &= 10\log \frac{I}{{{{10}^{ - 12}}}}\\3.9 &= \log \frac{I}{{{{10}^{ - 12}}}}\\I &= {10^{3.9}} \times {10^{ - 12}}\\I &= 7.94 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\end{align}\)

Therefore, the intensity of a sound is \(7.94 \times {10^{ - 9}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\)

Find Study Materials for

Create Study Materials

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

Step by Step Solution

Step1: Given Data

Step 2: Loudness

Step 3: Calculation of the intensity of the first sound

Step 4: Calculation of the intensity of the second sound

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Select your language

College Physics (Urone)

Answers without the blur.

Short Answer

Step by Step Solution

Step1: Given Data

Step 2: Loudness

Step 3: Calculation of the intensity of the first sound

Step 4: Calculation of the intensity of the second sound

Most popular questions for Physics Textbooks

Want to see more solutions like these?

Recommended explanations on Physics Textbooks

Work Energy and Power

Radiation

Astrophysics

Physics of Motion

Scientific Method Physics

Fluids

Torque and Rotational Motion

Nuclear Physics

Fields in Physics

Measurements

Space Physics

Electricity

Physical Quantities and Units

Medical Physics

Electrostatics

Further Mechanics and Thermal Physics

Mechanics and Materials

Engineering Physics

Energy Physics

Force

Particle Model of Matter

Waves Physics

Magnetism

Modern Physics

Atoms and Radioactivity

Dynamics

Electricity and Magnetism

Conservation of Energy and Momentum

Fundamentals of Physics

Kinematics Physics

Circular Motion and Gravitation

Linear Momentum

Rotational Dynamics

Oscillations

Translational Dynamics

Geometrical and Physical Optics

Thermodynamics

Magnetism and Electromagnetic Induction

Electromagnetism

Electric Charge Field and Potential

Turning Points in Physics