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Q43PE

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College Physics (Urone)
Found in: Page 630

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Short Answer

If a wind instrument, such as a tuba, has a fundamental frequency of 32.0 Hz, what are its first three overtones? It is closed at one end. (The overtones of a real tuba are more complex than this example, because it is a tapered tube.)

The first three overtones are 96 Hz, 160 Hz, 224 Hz.

See the step by step solution

Step by Step Solution

Step 1: Given Data

The fundamental frequency is 32 Hz.

Step 2: Calculation of the harmonics

The resonance frequencies of a tube closed at one end are,

fn=nv4I, n=1,3,5,...

The fundamental frequency is f1 = 32 Hz

The second harmonic is,

f3 = 3×v2I = 3 × 32 = 96 Hz

The second harmonic is,

f5 = 5×V2I = 5 × 32 = 160 Hz

The third harmonic is,

f7 = 7 V2I = 7 × 32 = 224 Hz

Hence, the first three overtones are 96 Hz, 160 Hz, 224 Hz.

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