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Q 29PE

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College Physics (Urone)
Found in: Page 318

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Short Answer

Question: A device for exercising the upper leg muscle is shown in Figure , together with a schematic representation of an equivalent lever system. Calculate the force exerted by the upper leg muscle to lift the mass at a constant speed. Explicitly show how you follow the steps in the Problem- Solving Strategy for static equilibrium in Applications of Statistics, Including Problem-Solving Strategies.

The force exerted by the upper leg muscle is 1715 N.

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Step by Step Solution

Step 1: Definition of the force

A force is an external factor that can change the rest or motion of a body. It has a size and a general direction.

Step 2: Understanding the free body diagram

The diagram for the leg muscles is shown below:

The perpendicular distance of the weight from the pivot point is r=35 cm.

The perpendicular distance of the applied force from the pivot point is r'=2.0 cm.

Step 3: Calculation of the force

As the upper leg muscle lifts the mass at a constant speed, the net force is zero. So, we can write,

T=mg=10×9.8=98 N

The torque about the pivot point is zero. So, we can write,

FMr'-Tr=0FM=Trr'=98×352=1715 N

Hence, the force is 1715 N.

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