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Expert-verified Found in: Page 471 ### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000 # Question: Dry air is 78.1% nitrogen. What is the partial pressure of nitrogen when the atmospheric pressure is 1.01×105 N/m2?

The partial pressure of nitrogen is $7.89×{10}^{4}N/{m}^{2}$

See the step by step solution

## Step 1: Introduction

We apply the formula for partial pressure which is to find partial pressure by multiplying nitrogen percentage by total pressure.

## Step 2: Given parameters and formula for partial pressure

Total pressure = Atmospheric pressure =$\text{1.01}×{\text{10}}^{\text{5}}{\text{N/m}}^{2}$

Percentage of nitrogen =78.1%

The formula for partial pressure ${\text{P}}_{\text{partial}}\text{=}\frac{\text{% Nitrogen}}{\text{100}}×{\text{P}}_{\text{total}}$

Here, Ppartial partial pressure and Ptotal total pressure.

## Step 3: Calculate the partial pressure

The partial pressure of nitrogen in the atmosphere

Therefore, partial pressure of nitrogen is $${\rm{7}}{\rm{.89 \times 1}}{{\rm{0}}^{\rm{4}}}\;{\rm{N/}}{{\rm{m}}^{\rm{2}}}$$ ### Want to see more solutions like these? 