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Q40PE

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College Physics (Urone)
Found in: Page 124

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Short Answer

An eagle is flying horizontally at a speed of 3.00m/s when the fish in her talons wiggles loose and falls into the lake 5.00 m below. Calculate the velocity of the fish relative to the water when it hits the water.

The final velocity of the fish relative to water when it hits the water, vf = 10.3 m/s.

See the step by step solution

Step by Step Solution

Step 1: Definition of final velocity

When gravity first exerts a force on an item, its initial velocity indicates how fast it travels. The final velocity, on the other hand, is a vector number that measures a moving body's speed and direction after it has reached its maximum acceleration.

Given data:

  • Speed of the eagle in the x-direction, vix = 3.00 m/s.
  • Vertical displacement of the fish to the lake, ∆y = 5.00 m.
  • The initial vertical component, viy = 0 m/s.
  • Acceleration of the fish in the vertical direction, ay = - -9.8m/s2.

 Step 2: Finding final velocity of fish

To find the final velocity in the negative y-direction, we have the kinematic equation

Vfy2=Vi2+2ayY

Substitute the values in the above equation, we get

Vfy2=0+2×(-9.8)×(-5.00)Vfy2=98Vfy=±98 =±9.9m/s

We take only the negative value because of this velocity in the negative y-direction.

So, Vfy=-9.9m/s

Now acceleration in the horizontal direction, ax = 0 m/s2 {since, g = 0 m/s2 }.

So the final velocity of the fish in the x-direction is equal to the initial velocity of the fish in the x-direction3.00 = m/s.

That is, Vfx=Vix=3.00m/s

So we have, Vfx=3.00m/sand Vfy=-9.90m/s

These two velocities are the two components of the final velocity of the fish, vf .

The resultant vector

Vf=(3.00)2+(-9.90)2 =10.3m/s

The final velocity of the fish is 10.3 m/s.

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