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Q65E

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College Physics (Urone)
Found in: Page 125

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Short Answer

An athlete crosses a -m-wide river by swimming perpendicular to the water current at a speed of m/s relative to the water. He reaches the opposite side at a distance m downstream from his starting point. How fast is the water in the river flowing with respect to the ground? What is the speed of the swimmer with respect to a friend at rest on the ground?

The total time taken to cross the river is 50s. The velocity of the water will be 0.8 m/s. The velocity of the swimmer w.r.t his friend at rest on the ground is 9.8m/s.

See the step by step solution

Step by Step Solution

Step 1: Definition of velocity

Velocity is the rate of change in position of an item in motion as seen from a specific frame of reference and measured by a specific time standard.

The velocity of the swimmer relative to the water is Vsw = 0.5m/s.

He is swimming at a velocity perpendicular to the current. We know the distance covered by him in the positive direction

Step 2: Time is taken by the swimmer

The time is taken by him to cross the river:

V=dt0.5=25tt=50 s

The total time taken to cross the river is 50 s.

Step 3: Velocity of the water with respect to earth

The velocity of the water w.r.t earth:

Vwe=dt=4050=0.8 ms

The velocity of the water will be 0.8m/s

Step 4: Velocity of the swimmer w.r.t friend at rest on the ground

The velocity will be calculated by the following equation:

t=50 sD=252+402D=47.2 m

Using the above equation, we can calculate the speed:

V=dt=47.250=0.94 ms

The velocity of the swimmer w.r.t his friend at rest on the ground is 0.94 m/s.

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