Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear?

The answer is $5 \times 10^{7}$ revolutions.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Concept and calculation of the number of revolutions of the tires

The radius of each of the tires is 0.260 m.
The distance traveled is 80,000 km.

The distance covered in one revolution of the tires will be their circumference, i.e., $2 π r$ .

Putting the value in the expression, we get :

$\begin{matrix} d = 2 \times (3.14) \times (0.260) \\ d = 1.6328 m \end{matrix}$

Step 2: Calculation of the number of revolutions of the tires

$\begin{matrix} n = \frac{(80, 000 km) \times (\frac{1000 m}{1 km})}{1.6328 m} \\ = 4.9 \times 10^{7} \\ \approx 5 \times 10^{7} revolutions \end{matrix}$

Hence, the automobile’s tires complete about $5 \times 10^{7} revolutions$ to travel the total distance of 80,000 km.

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College Physics (Urone)

Answers without the blur.

Short Answer

An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear?

Step by Step Solution

Step 1: Concept and calculation of the number of revolutions of the tires

Step 2: Calculation of the number of revolutions of the tires

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College Physics (Urone)

Answers without the blur.

Short Answer

An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear?

Step by Step Solution

Step 1: Concept and calculation of the number of revolutions of the tires

Step 2: Calculation of the number of revolutions of the tires

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