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Q6.1-3PE

Expert-verified
Found in: Page 221

### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

# An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear?

The answer is $5×{10}^{7}$ revolutions.

See the step by step solution

## Step 1: Concept and calculation of the number of revolutions of the tires

• The radius of each of the tires is 0.260 m.
• The distance traveled is 80,000 km.

The distance covered in one revolution of the tires will be their circumference, i.e., ${\mathbf{2}}{\mathbit{\pi }}{\mathbit{r}}$.

Putting the value in the expression, we get :

$\begin{array}{c}d=\text{2}×\text{(3.14)}×\text{(0.260)}\\ d=\text{1.6328 m}\end{array}$

## Step 2: Calculation of the number of revolutions of the tires

Hence, the automobile’s tires complete about $5×{10}^{7}\text{ }\mathrm{revolutions}$ to travel the total distance of 80,000 km.