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Q6.1-5PE

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Found in: Page 221

### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

# A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher’s hand is ${\mathbf{35}}{\mathbf{.}}{\mathbf{0}}{\mathbf{\text{ m/sec}}}$ and the ball is 0.300 m from the elbow joint, what is the angular velocity of the forearm?

The angular velocity of the forearm is $166.66\text{ rad/s}$.

See the step by step solution

## Step 1: Concept used and given data

The distance acts as the radius for the circular track followed by the pitcher's hand before pitching.

• The velocity of the ball in the pitcher’s hand is $35.0\text{ m/sec}$.
• The distance between the ball and the elbow joint is 0.300 m.

## Step 2: Explanation and calculation

The relationship between the angular velocity and linear velocity is given as follows:

Before pitching, the ball is in the hand of the baseball pitcher.

Therefore, the angular velocity of the forearm is equal to the angular velocity of the ball.

The angular velocity of the forearm can be calculated as:

$\omega =\frac{v}{r}$

Putting the values in the above equation, we get:

$\begin{array}{c}\omega =\frac{35}{0.300}\\ =166.66\text{ rad/s}\end{array}$

Therefore, the angular velocity is $166.66\text{ rad/s}$.