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Expert-verifiedA severely myopic patient has a far point of 5.00 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him?
The power of his eye must be reduced by 20.0 D.
The unit of measurement for the optical power of a lens or curved mirror is the dioptre of power of a lens, which is equal to the reciprocal of focal length.
The lens-to-retina distance is, .
The far point for the myopic patient is, .
The power of a normal person is P = 50 D
The power of the severely myopic eye Pmyopic can be obtained using:
...............(1)
And, the number of diopters PCorrected can be obtained using,
.................(2)
Substitute values in equation (1) and it gives,
Substituting data from equation (3) in equation (2), which gives,
Therefore, the power of the eye must be reduced by 20 D.
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