Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

A student’s eyes, while reading the blackboard, have a power of 51.0 D. How far is the board from his eyes?

The board is 1 m far from the student's eyes.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Definition of dioptre lens

The unit of measurement for the optical power of a lens or curved mirror is the dioptre of power of a lens, which is equal to the reciprocal of focal length.

Step 2: Given information and Formula to be used

The power of a student’s eye is P = 51.0 D

The lens-to-retina distance is, ${{\rm{d}}_{\rm{i}}} = {\rm{2}}{\rm{.00 cm}}\left( {\frac{{1\;{\rm{m}}}}{{100\;{\rm{cm}}}}} \right) = {\rm{0}}{\rm{.02 m}}$.

Step 3: How far is the board from his eyes?

The power of the eyes of a normal person can be calculated using the formula,

$P = (\frac{1}{d_{\circ}} + \frac{1}{d_{i}}) 51.0 D = (\frac{1}{0.02 m} + \frac{1}{d_{\circ}}) 51.0 D = 51.0 D + \frac{1}{d_{\circ}} \frac{1}{d_{\circ}} = 1.0 D$

This result in the value of

$\frac{1}{d_{\circ}} = 1.0 D (\frac{1 m^{- 1}}{1 D}) d_{\circ} = 1 m$

Therefore, the board is 1 m from the student's eyes.

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College Physics (Urone)

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Short Answer

A student’s eyes, while reading the blackboard, have a power of 51.0 D. How far is the board from his eyes?

Step by Step Solution

Step 1: Definition of dioptre lens

Step 2: Given information and Formula to be used

Step 3: How far is the board from his eyes?

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College Physics (Urone)

Answers without the blur.

Short Answer

A student’s eyes, while reading the blackboard, have a power of 51.0 D. How far is the board from his eyes?

Step by Step Solution

Step 1: Definition of dioptre lens

Step 2: Given information and Formula to be used

Step 3: How far is the board from his eyes?

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