Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

The power of a physician’s eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

The feature is 33.3 cm from the physician's eyes.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Definition of dioptre lens

The unit of measurement for the optical power of a lens or curved mirror is the dioptre of power of a lens, which is equal to the reciprocal of focal length.

Step 2: Given information and Formula to be used

Power of the physician’s eyes P = 53.0 D.

The lens-to-retina distance is, $d_{i} = 2.00 c m (\frac{1 m}{100 c m}) = 0.02 m$ .

Step 3: How far from her eyes is the feature being examined

The power of the eyes of a normal person can be calculated as,

$P = (\frac{1}{d_{\circ}} + \frac{1}{d_{i}}) 53.0 D = (\frac{1}{0.02 m}) + \frac{1}{d_{\circ}} \frac{1}{d_{\circ}} = 3.0 D$

Substituting data values in the above expression gives,

$d_{\circ} = \frac{1}{3.0 D} (\frac{1 D}{1 m^{- 1}}) = 0.334 m (\frac{100 c m}{1 m}) = 33.4 c m$

Therefore, the feature is 33.3 cm from the physician's eyes.

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College Physics (Urone)

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Short Answer

The power of a physician’s eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

Step by Step Solution

Step 1: Definition of dioptre lens

Step 2: Given information and Formula to be used

Step 3: How far from her eyes is the feature being examined

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College Physics (Urone)

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Short Answer

The power of a physician’s eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

Step by Step Solution

Step 1: Definition of dioptre lens

Step 2: Given information and Formula to be used

Step 3: How far from her eyes is the feature being examined

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