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College Physics (Urone)
Found in: Page 997

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Short Answer

Calculate the wavelength of light that has its third minimum at an angle of 30.0º when falling on double slits separated by 3.00 µm.

The wavelength of the light is 600 nm.

See the step by step solution

Step by Step Solution

Step 1: Given data

The angle for the third minimum is 30.0°

The separation of the double slits is d=3.00 μm10-°1 μm=3.00×10-6 m

Step 2: Finding the wavelength of the light

A formula for the angle of the third-order minimum can be expressed as,

d sin θ=52λ………………………….(1)

Substituting the given data in equation (1), we get,

3.00×10-6m×sin30.0°=52×λλ=1.50×10-6 m2.5λ=0.600×10-6 m1 nm10-9 mλ=600 nm

Thus, the distance between two slits is 600 nm.

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