Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

Calculate the wavelength of light that has its third minimum at an angle of 30.0º when falling on double slits separated by 3.00 µm.

The wavelength of the light is $^{600 nm}$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given data

The angle for the third minimum is $^{30.0 °}$

The separation of the double slits is $^{d = 3.00 μ m (\frac{10^{- °}}{1 μ m}) = 3.00 \times 10^{- 6} m}$

Step 2: Finding the wavelength of the light

A formula for the angle of the third-order minimum can be expressed as,

$d \sin θ = \frac{5}{2} λ$ ………………………….(1)

Substituting the given data in equation (1), we get,

$3.00 \times 10^{- 6} m \times \sin (30.0 °) = \frac{5}{2} \times λ λ = (\frac{1.50 \times 10^{- 6} m}{2.5}) λ = 0.600 \times 10^{- 6} m (\frac{1 n m}{10^{- 9} m}) λ = 600 n m$

Thus, the distance between two slits is $^{600 nm}$ .

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College Physics (Urone)

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Short Answer

Calculate the wavelength of light that has its third minimum at an angle of 30.0º when falling on double slits separated by 3.00 µm.

Step by Step Solution

Step 1: Given data

Step 2: Finding the wavelength of the light

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College Physics (Urone)

Answers without the blur.

Short Answer

Calculate the wavelength of light that has its third minimum at an angle of 30.0º when falling on double slits separated by 3.00 µm.

Step by Step Solution

Step 1: Given data

Step 2: Finding the wavelength of the light

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