Book edition 1st Edition

Author(s) Paul Peter Urone

Pages 1272 pages

ISBN 9781938168000

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Short Answer

What is the wavelength of light falling on double slits separated by 2.00 µm if the third-order maximum is at an angle of 60.0º ?

The wavelength of the light is $^{577 nm}$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given data

The angle for the third minimum is $^{60 . 0^{0}}$

The separation of the double slits is $d = 2.00 μm (\frac{10^{- 6} m}{1 μm}) = 2.00 \times 10^{- 6} m$

Step 2: Finding the wavelength of the light

A formula for the angle of the third-order maximum can be expressed as,

$dsinθ = 3 λ . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)$

Substituting the given data in equation (1), we get,

$2.00 \times 10^{- 6} m \times \sin (60 . 0^{0}) = 3 \times λ λ = (\frac{1.732 \times 10^{- 6} m}{3}) λ = 0.577 \times 10^{- 6} m (\frac{1 nm}{10^{- 9} m}) λ = 577 nm$

Thus, the distance between two slits is $^{577 nm}$ .

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Short Answer

What is the wavelength of light falling on double slits separated by 2.00 µm if the third-order maximum is at an angle of 60.0º ?

Step by Step Solution

Step 1: Given data

Step 2: Finding the wavelength of the light

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College Physics (Urone)

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Short Answer

What is the wavelength of light falling on double slits separated by 2.00 µm if the third-order maximum is at an angle of 60.0º ?

Step by Step Solution

Step 1: Given data

Step 2: Finding the wavelength of the light

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