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College Physics (Urone)
Found in: Page 997

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Short Answer

What is the wavelength of light falling on double slits separated by 2.00 µm if the third-order maximum is at an angle of 60.0º ?

The wavelength of the light is577 nm.

See the step by step solution

Step by Step Solution

Step 1: Given data

The angle for the third minimum is60.00

The separation of the double slits is d=2.00μm10-6 m1 μm=2.00×10-6 m

Step 2: Finding the wavelength of the light

A formula for the angle of the third-order maximum can be expressed as,

dsinθ =3λ...............................(1)

Substituting the given data in equation (1), we get,

2.00×10-6 m×sin60.00=3×λλ=1.732×10-6 m3λ=0.577×10-6 m1 nm10-9 mλ=577 nm

Thus, the distance between two slits is 577 nm.

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