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College Physics (Urone)
Found in: Page 997
College Physics (Urone)

College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

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Short Answer

What is the highest-order maximum for 400-nm light falling on double slits separated by 25.0 µm?

The Highest-order maximum for 400-nm light falling on double slits separated by 25.0 µm is62.

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Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Given data

The wavelength of the violet light isλ=400 nm10-9 m1 nm=4.0×10-7 m

The separation between the two slits isd=25 μm10-6 m1 nm=2.5×10-5 m

Step 2: Finding the highest-order maximum

A formula for the angle of the mth-order maximum can be expressed as,

dsin θ=mλ..................................(1)

The highest order occurs when sin θ=1.

Therefore, the substitute for these values in equation (1) will give,

d=mλm=dλm=2.5' 10-5 m4.0' 10-7 mm=62.5

Therefore, we will get a maximum order of m : 62

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