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Q27 PE
Expert-verifiedUsing energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 20.0 m above water with an initial speed of 15.0 m/s strikes the water with a speed of 24.8 m/s independent of the direction thrown.
The rock will strike the water with a speed of and is independent of the direction thrown.
Conservation of energy: An isolated system's total energy is always conserved. In other words, the energy neither be created nor be destroyed; it can be only transformed from one form to another.
Mathematically,
(1.1)
Here, m is the mass of the rock, is the final velocity of the rock ( as the rock stops after striking the water), is the initial velocity of the rock, g is the acceleration due to gravity , is the final height ( as the rock strikes the water), and is the initial height or the height of the bridge .
Rearranging equation (1.1) to get an expression for the final velocity,
(1.1)
When the rock is thrown downward with initial velocity will be positive i.e., . The final velocity can be calculated using equation (1.2).
Putting all known values in equation (1.2),
Therefore, the rock will strike the water with a speed of when thrown downward.
When the rock is thrown downward with initial velocity will be negative i.e. . The final velocity can be calculated using equation (1.2).
Putting all known values in equation (1.2),
Therefore, the rock will strike the water with a speed of when thrown downward.
From the above discussion it is clear that the rock will strike the water with a speed of and is independent of the direction thrown.
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