Suggested languages for you:

Americas

Europe

Q33 PE

Expert-verifiedFound in: Page 225

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**What is the cost of operating a 3.00-W**

The cost of operation electric clock for a year is *$2.37*.

**Power is defined as the rate at which energy is expended. **

The power is defined as,

\(P = \frac{E}{T}\) (1.1)

Here, *E* is the energy consumed and *T* is the time.

Rearranging equation (1.1) in order to get an expression for the energy consumption,

*E=PT* (1.2)

The commercial unit of energy is kilowatt-hour (kW.h).

The energy consumption of an *3.00-W* electric clock in a year can be calculated using equation (1.2).

Putting all known values in equation (1.2),

\(\begin{aligned}E &= \left( {3.00{\rm{ W}}} \right) \times \left( {1{\rm{ year}}} \right)\\ &= \left( {3.00{\rm{ W}}} \right) \times \left( {\frac{{1{\rm{ kW}}}}{{1000{\rm{ W}}}}} \right) \times \left( {1{\rm{ year}}} \right) \times \left( {\frac{{365{\rm{ day}}}}{{1{\rm{ year}}}}} \right) \times \left( {\frac{{24{\rm{ h}}}}{{1{\rm{ day}}}}} \right)\\ &= 26.28{\rm{ kW}} \cdot {\rm{h}} \end{aligned}\)

Since, the cost of electricity is *$0.0900 per kW.h*. Therefore, cost of operation of an electric clock for a year is,

\(\begin{aligned}{\rm{Cost}} = {\rm{Rate}} \times E \end{aligned}\)

Putting all known values,

\(\begin{aligned}{\rm{Cost}} &= \left( {\$ 0.0900{\rm{ per kW}} \cdot {\rm{h}}} \right) \times \left( {26.28{\rm{ kW}} \cdot {\rm{h}}}\right)\\\approx \$ 2.37\end{aligned}\)

Therefore, the required cost of operation electric clock for a year is *$2.37.*

94% of StudySmarter users get better grades.

Sign up for free