Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q44PE

Expert-verified
College Physics (Urone)
Found in: Page 262

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

(a) How long can you rapidly climb stairs \(\left( {116/{\rm{min}}} \right)\) on the \(93.0{\rm{ kcal}}\) of energy in a \(10.0 - {\rm{g}}\) pat of butter?

(b) How many flights is this if each flight has \(16\) stairs?

(a) A person can climb stairs for \(9.47{\rm{ s}}\) using \(93.0{\rm{ kcal}}\) of energy.

(b) Number of flights are \(69\).

See the step by step solution

Step by Step Solution

Step 1: Definition of Concepts 

Power: The quantity of energy transferred or transformed per unit of time is known as power. The watt is the unit of power in the International System of Units.

Mathematically,

\(P = \frac{E}{T}\)

Here, \(E\) is the energy consumption, and \(T\) is the time.

Step 2: Calculate the time of the person can climb

(a)

The time for which a can climb can calculated using equation (1.1).

Rearranging equation (1.1) in order to get an expression for time,

\(T = \frac{E}{P}\)

Here, \(E\) is the energy consumed by the person \(\left( {E = 93.0{\rm{ kcal}}} \right)\), and \(P\) is the power required to climb stairs \(\left( {P = 685{\rm{ W}}} \right)\).

Putting all known values,

\(\begin{array}{c}T = \frac{{93.0{\rm{ kcal}}}}{{685{\rm{ W}}}}\\ = \frac{{\left( {93.0{\rm{ kcal}}} \right) \times \left( {\frac{{1000{\rm{ cal}}}}{{1{\rm{ kcal}}}}} \right) \times \left( {\frac{{4.184{\rm{ J}}}}{{1{\rm{ cal}}}}} \right)}}{{685{\rm{ W}}}}\\ = 568{\rm{ sec}} \times \left( {\frac{{1{\rm{ min}}}}{{60{\rm{ sec}}}}} \right)\\ = 9.47{\rm{ s}}\end{array}\)

Therefore, a person can climb stairs for \(9.47{\rm{ s}}\) using \(93.0{\rm{ kcal}}\) of energy.

Step 3: Find the number of flights

(b)

Consider the given information:

Number of stairs a person can climb is \({n_s} = 116/{\rm{min}}\).

Number of stairs per flight \({n_f} = 16/{\rm{flight}}\).

Time taken to climb \(T = 9.47{\rm{ min}}\).

The number of flights is,

\(N = \frac{{{n_s}T}}{{{n_f}}}\)

Putting all known values,

\(\begin{array}{c}N = \frac{{\left( {116/{\rm{min}}} \right) \times \left( {9.47{\rm{ min}}} \right)}}{{\left( {16/{\rm{flight}}} \right)}}\\ = 68.66{\rm{ flights}}\\ \approx 69{\rm{ flights}}\end{array}\)

Therefore, the required number of flights is \(69\).

Most popular questions for Physics Textbooks

Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.