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Fundamentals Of Physics
Found in: Page 1247

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Short Answer

What is the acceleration of a silver atom as it passes through the deflecting magnet in the Stern–Gerlach experiment of Fig. 40-8 if the magnetic field gradient is 1.4 T/mm?

The acceleration of the silver atom as it passes through the deflecting magnet in the experiment is 7.2×104 m/s2.

See the step by step solution

Step by Step Solution

Step 1: The given data:

Gradient of the magnetic field, dBdz=1.4 T/mm

Step 2: Understanding the concept of force of a Stern-Gerlach Experiment:

Using the formula of force from second Newton's law in the force value of the Stern-Gerlach Experiment, we can get the required acceleration by substituting the obtained data from the experiment.

Formulas:

The force is due to Newton’s second law of motion,

F = ma

….. (1)

The force obtained due to gradient change in a magnetic field,

F=μB=dBdzma=μB=dBdz

….. (2)

Where, the Bohr magneton, μB=9.27×10-24 J/T

Step 3: Calculation of the value of the acceleration of the silver atom:

Using the value of force from equation (2) in equation (1), the value of the acceleration of the silver atoms as follows: (Using the data given in the Sample problem, m=1.8×10-25kg)

a=μsdBdzm =9.27×10-24J/T×1.4×103 T/m1.8×10-25 kg =7.2×104 m/s2

Hence, the value of the acceleration of the silver atom is 7.2×104 m/s2 .

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