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Expert-verifiedAn electron in a multi-electron atom has For this electron, what are (a) the value of I, (b) the smallest possible value of n, and (c) the number of possible values of ?
An electron in a multi-electron atom has .
For every value of the orbital quantum number, there exist (21+1) values of magnetic quantum number ranging from -I to +I. Thus, the maximum value of this magnetic quantum number is equal to the value of the orbital quantum number. Now, for every value of the principal quantum number, there are n values of I ranging from 0 to (n-1) . Thus, the smallest value of n is given by (I+1). Now, every electron has two spin orientations, thus the value of the magnetic quantum number is determined by these spins.
Formula:
The smallest possible value of n is
n =I +1 ….. (1)
The value of considering the table is given by,
Hence, the value is 4.
Using the above value of I=4 in equation (1), we can get the smallest possible value of n as follows:
n = 4 + 1
=5
Hence, the smallest possible value of is 5.
Using the concept, we know that there are two possible spin orientations of electron,
Hence, there are two possible values.
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